A gas expands adiabatically from \( 5 \, \text{L} \) to \( 20 \, \text{L} \), reducing its temperature
from \( 500 \, \text{K} \) to \( 250 \, \text{K} \). If \( 1 \, \text{mole} \) of gas is used and \( R =
8.3 \, \text{J mol}^{-1} \text{K}^{-1} \), what is the work done by the gas? (\( \gamma = 1.5 \))
For adiabatic process: \( W = \frac{\mu R (T_1 - T_2)}{\gamma - 1} \).
\( \mu = 1 \), \( R = 8.3 \), \( T_1 = 500 \), \( T_2 = 250 \), \( \gamma = 1.5 \).
\( W = \frac{1 \times 8.3 \times (500 - 250)}{1.5 - 1} = \frac{8.3 \times 250}{0.5} = 4150 \, \text{J}
\).